3.1535 \(\int \frac{1}{\sqrt{-3+b x} \sqrt{2+b x}} \, dx\)

Optimal. Leaf size=21 \[ \frac{2 \sinh ^{-1}\left (\frac{\sqrt{b x-3}}{\sqrt{5}}\right )}{b} \]

[Out]

(2*ArcSinh[Sqrt[-3 + b*x]/Sqrt[5]])/b

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Rubi [A]  time = 0.0057734, antiderivative size = 21, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {63, 215} \[ \frac{2 \sinh ^{-1}\left (\frac{\sqrt{b x-3}}{\sqrt{5}}\right )}{b} \]

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[-3 + b*x]*Sqrt[2 + b*x]),x]

[Out]

(2*ArcSinh[Sqrt[-3 + b*x]/Sqrt[5]])/b

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
x] && GtQ[a, 0] && PosQ[b]

Rubi steps

\begin{align*} \int \frac{1}{\sqrt{-3+b x} \sqrt{2+b x}} \, dx &=\frac{2 \operatorname{Subst}\left (\int \frac{1}{\sqrt{5+x^2}} \, dx,x,\sqrt{-3+b x}\right )}{b}\\ &=\frac{2 \sinh ^{-1}\left (\frac{\sqrt{-3+b x}}{\sqrt{5}}\right )}{b}\\ \end{align*}

Mathematica [A]  time = 0.0097141, size = 41, normalized size = 1.95 \[ \frac{2 \sqrt{b x-3} \sin ^{-1}\left (\frac{\sqrt{3-b x}}{\sqrt{5}}\right )}{b \sqrt{3-b x}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[-3 + b*x]*Sqrt[2 + b*x]),x]

[Out]

(2*Sqrt[-3 + b*x]*ArcSin[Sqrt[3 - b*x]/Sqrt[5]])/(b*Sqrt[3 - b*x])

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Maple [B]  time = 0.007, size = 66, normalized size = 3.1 \begin{align*}{\sqrt{ \left ( bx-3 \right ) \left ( bx+2 \right ) }\ln \left ({ \left ( -{\frac{b}{2}}+{b}^{2}x \right ){\frac{1}{\sqrt{{b}^{2}}}}}+\sqrt{{b}^{2}{x}^{2}-bx-6} \right ){\frac{1}{\sqrt{bx-3}}}{\frac{1}{\sqrt{bx+2}}}{\frac{1}{\sqrt{{b}^{2}}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x-3)^(1/2)/(b*x+2)^(1/2),x)

[Out]

((b*x-3)*(b*x+2))^(1/2)/(b*x-3)^(1/2)/(b*x+2)^(1/2)*ln((-1/2*b+b^2*x)/(b^2)^(1/2)+(b^2*x^2-b*x-6)^(1/2))/(b^2)
^(1/2)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x-3)^(1/2)/(b*x+2)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 1.98939, size = 70, normalized size = 3.33 \begin{align*} -\frac{\log \left (-2 \, b x + 2 \, \sqrt{b x + 2} \sqrt{b x - 3} + 1\right )}{b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x-3)^(1/2)/(b*x+2)^(1/2),x, algorithm="fricas")

[Out]

-log(-2*b*x + 2*sqrt(b*x + 2)*sqrt(b*x - 3) + 1)/b

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{b x - 3} \sqrt{b x + 2}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x-3)**(1/2)/(b*x+2)**(1/2),x)

[Out]

Integral(1/(sqrt(b*x - 3)*sqrt(b*x + 2)), x)

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Giac [A]  time = 1.14834, size = 32, normalized size = 1.52 \begin{align*} -\frac{2 \, \log \left ({\left | -\sqrt{b x + 2} + \sqrt{b x - 3} \right |}\right )}{b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x-3)^(1/2)/(b*x+2)^(1/2),x, algorithm="giac")

[Out]

-2*log(abs(-sqrt(b*x + 2) + sqrt(b*x - 3)))/b